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from hubertf@netbsd:

Try to tell what this really does.
Including a BUGS section on why it doesn't.
*roff code by wiz@, with some input from
Slava Semushin <slava.semushin@gmail.com>
ok millert
OPENBSD_4_1
jmc 18 years ago
parent
commit
ce684f6c93
1 changed files with 18 additions and 6 deletions
  1. +18
    -6
      src/lib/libc/string/strxfrm.3

+ 18
- 6
src/lib/libc/string/strxfrm.3 View File

@ -29,7 +29,7 @@
.\" OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
.\" SUCH DAMAGE.
.\"
.\" $OpenBSD: strxfrm.3,v 1.5 2005/08/12 18:34:32 jmc Exp $
.\" $OpenBSD: strxfrm.3,v 1.6 2007/02/19 19:09:27 jmc Exp $
.\"
.Dd June 29, 1991
.Dt STRXFRM 3
@ -42,12 +42,19 @@
.Ft size_t
.Fn strxfrm "char *dst" "const char *src" "size_t n"
.Sh DESCRIPTION
The
The idea of
.Fn strxfrm
function does something horrible (see
.Tn ANSI
standard).
In this implementation it just copies.
is to
.Dq un-localize
a string: the function transforms
.Ar src ,
storing the result in
.Ar dst ,
such that
.Xr strcmp 3
transformed strings return what
.Xr strcoll 3
on the original untransformed strings would return.
.Sh SEE ALSO
.Xr bcmp 3 ,
.Xr memcmp 3 ,
@ -60,3 +67,8 @@ The
.Fn strxfrm
function conforms to
.St -ansiC .
.Sh BUGS
Since locales are not fully implemented on
.Ox ,
.Fn strxfrm
just returns a copy of the original string.

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